Biden Is "Confident" This Democrat Has Got The Nom

Here's another vote of confidence that Hillary Clinton will power through to the White House. Speaking on Tuesday to Good Morning America's Robin Roberts, Vice President Joe Biden felt "confident" Clinton would become president. He told Roberts, "I feel confident that Hillary will be the nominee, and I feel confident she’ll be the next president." Considering the Democratic primaries aren't even over yet, this is pretty significant. Certainly, it's not a political bombshell of the magnitude of House Speaker Paul Ryan saying he's "just not ready" to endorse Trump last week, but it's still a powerful and old statement — if not an endorsement.

Biden has refrained from officially endorsing either Clinton or her opponent, Vermont Sen. Bernie Sanders. However, Biden has provided subtle tidbits of support for Clinton in the past, such as in an April interview with Mic, when he said, "I would like to see a woman elected ... Hillary's overwhelmingly qualified to be president." President Barack Obama has echoed his VP with a similar sentiment, albeit in a joke at the White House Correspondents' Dinner: "Next year at this time, someone else will be standing here in this very spot and it’s anyone guess who she will be."

Granted, it isn't so groundbreaking for Biden to feel confident about Clinton winning the nomination when she is very much set to do so. The Democratic frontrunner has had huge recent victories, such as in the New York and Acela primaries. Her delegate count soars above Sanders'. As CBS News noted, Clinton needs to just snag 17 percent of the remaining available delegates to seal the nomination.

What's a little more bold is Biden's proclamation that Clinton will not only win the Democratic nomination, but the presidential election, as well. Still, although the latest numbers from Quinnipiac University show Donald Trump and Clinton are close in battleground states, the former Secretary of State still has the edge in general, according to the RealClearPolitics average.